In an isosceles right angled triangle ABC , AB=ACin an isosceles triangle ABC AB is equal to AC is equal to 25 CM BC is equal to 14 centimetre calculate the altitude from a on BC
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after drawing altitude AD on BC prove triangle ABD and ADC congruent by SAS congruency
then by c.p.c.t. BD=DC
hence BD =1/2 BC
Hence BD =7 cm
then by c.p.c.t. BD=DC
hence BD =1/2 BC
Hence BD =7 cm
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