Question

In an isosceles right angled triangle ABC, AC = BC and angle ACB = 90. Find angle ABC.

Answer 1

Answer:

45°

Step-by-step explanation:

In right angled triangle,by angle sum property

∠ABC +∠ACB +∠CAB = 180

∠ABC +∠ABC +90 = 180 ( ∆ABC is isosceles triangle with AC =BC

2∠ABC = 180−90 = 90

∠ABC =90/2

∠ABC = 45°