Question

In an isosceles right angled triangle if the hypotenuse is 5 under root 2 cm then find the length of the sides of the triangle ??​

Answer 1

Answer:

let side of each side = x cm

hypotenuse= h=5√2

base=b= x cm

perpendicular= p= x cm

using phythagoras theorem,

(h)^2=(b)^2+(p)^2

(5√2)^2= x^2+x^2

25×2= 2(x)^2

50/2= x^2

25 =x^2

x=√25=5 cm

so length of each side is 5 cm

Answer 2

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$question \: -$

☞In an isosceles right angled triangle if the hypotenuse is 5 under root 2 cm then find the length of the sides of the triangle ?

Answer —

$→let \: each \: side \: will \: be \: x$

$→hypotenuse \: - \: 5√2$

$→base \: = x \: cm \: and \: perpendicular \: = \: x \: cm.$

$→( {hypotenuse})^{2} = ( {base})^{2} + ( {perpendicular})^{2}$

$→( {5√2})^{2} = {x \: }^{2} + {x}^{2}$

$→25 \: \times 2 \: = 2 {x}^{2}$

$→\frac{50 }{2} = {x}^{2}$

$→25 = {x}^{2}$

$→x = √25$

$☞x \: = 5cm.$

$hence \: length \: of \: each \: side \: is \: 5cm.$

hope it is helpful for you ✅✔☑

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