Question

In an isosceles right angled triangle, the perimeter is 20 metre. Find its area.

Answer 1

Answer:

Step-by-step explanation:

let say base = x m

then height = x m

as triangle is isoscelles

hypotaneous^2 = base^2 + height^2

hupotaneous^2 = x^2 + x^2

hypotaneous =( root2)x

perimeter = x + x + (root2)x

x ( 2 + (root2)) = 20

x = 20/(2+(root2))

area = (1/2)*(base * height)

area = (1/2)(x)*(x)

area= (1/2)x^2

area =( 1/2) (20/(2+(root2)))^2

area = (1/2)*(400)/(4 + 2 + 4root2)

area = 200/(6 + 4root2)

area = 100/(3 + 2root2)

area = 100/(3 + 2*1.414)

area = 100/(5.828)

area =17.16 m^2