Question

In
an
isosceles right triangle
A B C right
angled at A, the
2
Sin B cos c
=​

Answer 1

Answer:

Given  △ABC is an isosceles right triangle

∠B=90∘,∠A=∠C=45∘

⟹sin2A+cos2C−sin2B=sin245∘+cos245∘−sin290∘=(21)2+(21)2−(1)2=21+21−1=1−1=0