Question

In an isosceles right triangle ABC right angled at A, the value of 2SIN B COS C =​

Answer 1

Answer:

not fine cnt answer sorry

Step-by-step explanation:

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Answer 2

Answer:

1

Step-by-step explanation:

since ABC is an isosceles triangle,than its two angels are equal and angle BAC is 90° (given)

so the remaining angles will be 45°

so we get angle ABC=45°, angle BAC=90° and

angle BCA=45°

SIN B = 1/√2. (Angle B is 45° and sin 45° is 1/√2 )

COS C = 1/√2. ( Angle C is 45° and cos 45° is 1/√2)

therefore, 2SIN B COS C =

2×1/√2×1/√2

2/2= 1