In an isosceles right-triangle the square of the hypotenuse is 98cm2.Find the length of the congurant sides? after 98 cm 2 is square root
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In an isosceles right triangle two sides are equal
Given square of hypotenuse = 98 cm²
Let the sides be xcm [as they are equal, let both the sides be xcm]
We know that by pythagoras theorem
side² + side² = hyp²
⇒ x² + x² = 98
⇒ 2x² = 98
⇒ x² = 98/2
⇒ x² = 49
⇒ x = √49
∴ x = 7
∴The length of the congruent sides are 7cm and 7cm
Given square of hypotenuse = 98 cm²
Let the sides be xcm [as they are equal, let both the sides be xcm]
We know that by pythagoras theorem
side² + side² = hyp²
⇒ x² + x² = 98
⇒ 2x² = 98
⇒ x² = 98/2
⇒ x² = 49
⇒ x = √49
∴ x = 7
∴The length of the congruent sides are 7cm and 7cm
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4
Answer:
Step-by-step explanation:
In an isosceles right triangle two sides are equal
Given square of hypotenuse = 98 cm²
Let the sides be xcm [as they are equal, let both the sides be xcm]
We know that by pythagoras theorem
side² + side² = hyp²
⇒ x² + x² = 98
⇒ 2x² = 98
⇒ x² = 98/2
⇒ x² = 49
⇒ x = √49
∴ x = 7
∴The length of the congruent sides are 7cm and 7cm
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