Math, asked by jassfoji20, 10 months ago

in an isosceles trapezium ABCD,AB parallel to CD,AB =23 cm,CD=8 cm,BC=AD=12.5,find the area of trapezium?

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Answered by Anonymous

3

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area of trapezium=1/2×sum of parallel sides×h

1/2(23+8)×12.5 cm²

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