in an isosceles trapezium show that the opposite angles are supplementary
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2
Answer:
Given ABCD is isoscles trapezium in which AD = BC
To prove: (i) Angle A + Angle C = 180
(ii) Angle B + ZD = 180⁰
Proof:AB || CD
⇒ Angle A + Angle D = 180
But Angle A = Angle B[Trapezium is isosceles] Angle B + Angle D = 180° Similarly Angle A + Angle C = 180º
Hence the result.
Answered by
11
Answer:
Given
ABCD is isoscles trapezium in which AD=BC
To prove: (i)∠A+∠C=180
(ii)∠B+∠D=180°
Proof: AB∥CD
⇒∠A+∠D=180
But ∠A=∠B [Trapezium is isosceles]
∠B+∠D=180°
Similarly ∠A+∠C=180 °
Hence the result.
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