Math, asked by reenakaushal13396, 2 months ago

In an isosceles triangle ABC , AB=AC , Angle A = (2x+15) degree, angle B = (3x+20) degree and angle C = (x+25) degree, find the value of x.​

Answers

Answered by chandrakantamajhi54
0

Answer:

<A+<B+<C = 180°

(2x+15)° + (3x+20)° + (x+25)° = 180°

(6x+60)° = 180°

6x = 120°

x = 20°

Step-by-step explanation:

<A = 55°

<B = 80°

<C = 45°

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