Question

In an Isosceles triangle ABC, AB=AC.D is a point on BC such that BD=5 unit and CD=12 unit and angle DAC is a right angle.Then find AD.​

Answer 1

ANSWER

In △s ABD and ADC,

AD = AD (Common)

BD = CD (Given)

AB = AC (Given)

Hence, △ABD≅△ADC (SSS rule)

Thus, ∠ADB=∠ADC=x (By cpct)

∠ADB+∠ADC=180 (Angles on a straight line)

x+x=180

x=90

∠ADB=∠ADC=90

∘

or, AD is perpendicular to BC