In an isosceles triangle ABC, AB=BC if A= angle 52 degree , what is the measure of angle B.
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7
sum of all angles of a triangle = 180°
angle a + angle B+ angle C. = 180°
Angle B = angle C ( Base angles of an isosceles triangle are equal).
Let angle B an c be x° each.
52° + x° +x °. = 180°
2x °. = 180° - 52°
x. = 122° /2
x. = 61°
Ans.= Angle B is 61°.
angle a + angle B+ angle C. = 180°
Angle B = angle C ( Base angles of an isosceles triangle are equal).
Let angle B an c be x° each.
52° + x° +x °. = 180°
2x °. = 180° - 52°
x. = 122° /2
x. = 61°
Ans.= Angle B is 61°.
Answered by
3
Lets use angle sum property
that is angle A+ angle B+ angle C= 180*
So Let Angle B and C Be X degrees
we known that angle A= 52 degree
so the solution is
52+ x+x=180
2x+52=`180
2x=180-52=128
so x=128/2=64
x=64 degree
that is angle A+ angle B+ angle C= 180*
So Let Angle B and C Be X degrees
we known that angle A= 52 degree
so the solution is
52+ x+x=180
2x+52=`180
2x=180-52=128
so x=128/2=64
x=64 degree
Rishita2003:
verification 52+64+64=180
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