Question

in an isosceles triangle ABC AB is equals to BC and Angle b is equals to 70 degree find angle c and Angle a​

Answer 1

Step-by-step explanation:

Given: In a Δ ABC, AB = BC and ∠B = 70° ∠B = ∠C [Angles opposite to equal sides are equal]

Therefore, ∠B = ∠C = 70°

Sum of angles in a triangle = 180°

∠A + ∠B + ∠C = 180°

∠A + 70° + 70° = 180°

∠A = 180° – 140°

∠A = 40°

Answer 2

Answer:

AB = BC

Angle B = 70°

Let angle A be x.

Then, angle C = x (by property of angles opposing equal sides are equal).

$by \: angle \: sum \: property \: of \: triangle \\angle \: a + angle \: b + angle \: c = 180 \: \\ x + 70 + x = 180 \\ 2x + 70 = 180 \\ 2x = 180 - 70 \\ x = \frac{110}{2} \\ x = 55 \\ \\ hence \: angle \: a \: = 55 \: \\ and \: angle \: b = 55$