Question

In an isosceles triangle ABC, AD is the
perpendicular from vertex A to base BC.
Prove that triangle ABD is congruent to
triangle ACD.
DC​

Answer 1

UdayMehtani1Virtuoso

U can use RHS congruence rule.

In ∆ADB and ∆ADC

angleADB=angleADC=90° (since AD is perpendicular to BC)

AB=AC( since it is an isos triangle)

AND. AD=AD (common)

therefore the triangles are congruent.

BD=DC(by cpct)