Question

In an isosceles triangle ABC, AD is the perpendicular from vertex A to base BC. Prove that triangle ABC De is congruent to triangle ACD. ​
pls help​

Answer 1

Answer:ΔABD≅ΔACD  SSS

Step-by-step explanation:

In △ABD and △ACD,

AB=AC     (since △ABC is isosceles)

AD=AD     (common side)

BD=DC     (since △BDC is isosceles)

ΔABD≅ΔACD     SSS test of congruence,

∴∠BAD=∠CAD i.e. ∠BAP=∠PAC    [c.p.c.t]