In an isosceles triangle ABC, angle B = angle C = 2 angle A, find the 3 angles of a triangle. In a triangle PQR, angle P is 50 degrees more than angle Q and angle R is 20 degrees less than angle Q. What are the angles of the triangle?
Answers
Answer:
Step-by-step explanation:∠A+∠B+∠C=180⁰( Sum of interior angles of a triangle)
According to the question;
∠B=∠A
∠C=2∠A
Now substituting the value of ∠B and ∠C
∠A+∠A+2∠A=180
∠A=45
∠B=45
∠C=90
For triangle PQR;
∠P=50+∠Q;
∠R=∠Q-20;
∠P+∠Q+∠R=180( Sum of interior angles)
3∠Q+30=180
3∠Q=150
∠Q=50
∠P=100
∠R=30
Hey I hope it helps you <3
Step-by-step explanation:
First problem:-
A + B + C = 180°
[Given]
B = C = 2A
ATP,
A + B + C = 180°
=> A + 2A + 2A = 180°
=> 5A = 180°
=> A = 180°/5
=> A = 36°
Therefore,
B = C = 2A
B = C = 2 X 36° = 72
Now the second sum,
[Given]
P = Q + 50°
R = Q - 20°
Q + P + R = 180°
=> Q + Q + 50° + Q - 20° = 180°
=> 3Q + 30° = 180°
=> 3Q = 180° - 30°
=> 3Q = 150°
=> Q = 50°
Therefore,
P = Q + 50° = 50° + 50° = 100°
R = Q - 20° = 50° - 20° = 30°
Q = 50°
I hope this is correct, If it is, please mark it as the brainliest, thankyou
