Question

in an isosceles triangle ABC, angle BCA right angle .prove that ab2=2ac​

Answer 1

Step-by-step explanation:

Given data :

Δ ABC is a right Δ and also isosceles triangle.,

To prove:

\mathrm{AB}^{2}=2 \mathrm{AC}^{2}AB

2

=2AC

2

Step 1:

Proof:

Here,

Hypotenuse = AB

Also, as it is given that, ΔABC is isosceles,

Step 2:

AC = BC [equal sides of isosceles Δ]

Using Pythagoras theorem,

Step 3:

In Δ ABC, we have ;

\begin{lgathered}\begin{array}{l}{\mathrm{AB}^{2}=\mathrm{AC}^{2}+\mathrm{BC}^{2}} \\ {\mathrm{AB}^{2}=\mathrm{AC}^{2}+\mathrm{AC}^{2}}\end{array}\end{lgathered}

AB

2

=AC

2

+BC

2

AB

2

=AC

2

+AC

2

[AC = BC]

\mathrm{AB}^{2}=2 \mathrm{AC}^{2}

Hence proved

Answer 2

ur answer is attached....

hope it's helpful for u....