Question

In an isosceles triangle ABC, if AB = AC = 25 cm and BC = 14 cm, then the measure of altitude from A on BC is
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Answer 1

In triangle ABC

Let tge altitude be AD on BC

AC=25cm

AB=25cm

BC=14cm

Therefore DC= 1/2*BC

=1/2*14

=7

By Pythagoras theorem,

AD^2+CD^2=AC^2

AD^2+7^2=25^2

AD^2+49=625

AD^2=625-49

AD^2=576

AD=24

Therefore altitude from A on BC is 24 cm

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