In an isosceles triangle abc if ab=ac=25cm & bc=14cm then the length of the altitude from a on bc is
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since the altitude is onto side bc so it will be halved
a right angled triangle with hypotenuse as 25 and base as 7
so by pythogoras theorem----> (25)^2-(7)^2=625-49=576=24^2
the length of altitude is 24 cm
a right angled triangle with hypotenuse as 25 and base as 7
so by pythogoras theorem----> (25)^2-(7)^2=625-49=576=24^2
the length of altitude is 24 cm
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In triangle ABC
Let tge altitude be AD on BC
AC=25cm
AB=25cm
BC=14cm
Therefore DC= 1/2*BC
=1/2*14
=7
By Pythagoras theorem,
AD^2+CD^2=AC^2
AD^2+7^2=25^2
AD^2+49=625
AD^2=625-49
AD^2=576
AD=24
Therefore altitude from A on BC is 24 cm
Let tge altitude be AD on BC
AC=25cm
AB=25cm
BC=14cm
Therefore DC= 1/2*BC
=1/2*14
=7
By Pythagoras theorem,
AD^2+CD^2=AC^2
AD^2+7^2=25^2
AD^2+49=625
AD^2=625-49
AD^2=576
AD=24
Therefore altitude from A on BC is 24 cm
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