In an isosceles triangle abc, if ac=bc and ab^2 = 2 ac^2, then angle c=
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Answered by
4
▪Given that,
- AC = BC
- AB² = 2AC²
▪To find,
- Angle C
______________________________________
AB² = AC² + AC²
We are given AC = BC,
Now,
AB² = AC² + BC²
It is Pythagoras equation ( As it involves three sides of the triangle which is Hypotenuse² = side² + side² )
So from the above,
AB is the hypotenuse.
Since, AB is the hypotenuse, C is right angled.
So, The angle C measures 90°
Answered by
0
▪Given that,
AC = BC
AB² = 2AC²
▪To find,
Angle C
AB² = AC² + AC²
We are given AC = BC,
Now,
AB² = AC² + BC²
It is Pythagoras equation ( As it involves three sides of the triangle which is Hypotenuse² = side² + side² )
So from the above,
AB is the hypotenuse.
Since, AB is the hypotenuse, C is right angled.
So, The angle C measures 90°
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