In an isosceles triangle ABC If AC=BC and AB Square equals to 2AC square. Then measure of angle C is?
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Answered by
13
Answer:
Step-by-step explanation:
Given-AC=BC and (AB)^2=(2AC)^2
TO PROVE-Measure of anle C
PROOF-as given,
(AB)^2=(2AC)^2
(AB)^2=(AC+AC)^2
(AB)^2=(AC)^2+(BC)^2 (as givenAC=BC)
So,by converse of pythagoras theorem
Angle C =90°
Answered by
2
Correct question:-
ABC is an isosceles triangle with AC=BC. If AB^2=2AC^2 prove that ABC is a right triangle.
Given that:-
ABC is an isosceles triangle .
AC = BC
AB^2 = 2AC^2
To prove:-
ABC is a right triangle
_____________________________
Proof
AB² = 2AC² - (Given)
AB² = AC² + AC²
AB² = AC² + BC² - (As AC = BC)
Thus, AB is the largest side i.e the (Hypotenuse).
By the Converse of Pythagoras theorem,
∠C = 90°
Hence its a right angle triangle.
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