Question

in an isosceles triangle ABC if AC is equal to BC and AB square is equal to 2 AC square then find angle C

Answer 1

Hello there!

Thanks for the question.

So, It's given that

AC = BC

and also ,

AB² = 2AC²

From this,

You can write

AB² = AC² + AC²

This looks like Pythagoras theorem. But yeah, Comparison of just two sides won't make it complete. That's why We are given AC = BC,

Now our equation looks,

AB² = AC² + BC²

This is now looking like Pythagoras equation ( As it involves three sides of the given triangle) which is Hypotenuse² = side² + side²

So from the above relationship,

You can say AB is the hypotenuse.

Since, AB is the hypotenuse, C is right angled.

Simple, So The angle C measures 90°

Hope you are helped !

Answer 2

$\huge\sf{Answer}$

▪Given that,

• AC = BC

• AB² = 2AC²

▪To find,

• Angle C

______________________________________

AB² = AC² + AC²

We are given AC = BC,

Now,

AB² = AC² + BC²

It is Pythagoras equation ( As it involves three sides of the triangle which is Hypotenuse² = side² + side² )

So from the above,

AB is the hypotenuse.

Since, AB is the hypotenuse, C is right angled.

So, The angle C measures 90°

#BAL

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