In an isosceles triangle abc in which ab=ac, rhe measures of sides ab and the base bc are in the ratio 13 : 11 . If the perimeter of abc is 259 cm , find the measures of all its sides?
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Given AB : BC = 13 : 11 (Given)
Since AB = AC, then
⇒AB : AC : BC = 13 : 13 : 11
Define x:
Let x be the constant ratio
AB : AC : BC = 13x : 13x : 11x
Solve x:
The perimeter is 259 cm
13x + 13x + 11x = 259
37x = 259
x = 259 ÷ 37
x = 7
Find the sides:
13x = 13(7) = 91 cm
11x = 11(7) = 77 cm
Answer: The sides are 91 cm , 91 cm and 77 cm
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4
Answer:
91 cm
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