in an isosceles triangle ABC,measure of the base angles is 30 degree more than the measure of its vertex angle.find the measure of each angle.
Answers
Answered by
12
let x be the vertex angle
therefore base angles are x+30° each
therefore,
x + (x+30) + (x+30) = 180°
3x + 60 = 180°
3x = 120°
x = 40°
therefore the angles are 40°, 70° (40 + 30), and 70°
hope it answers your query
therefore base angles are x+30° each
therefore,
x + (x+30) + (x+30) = 180°
3x + 60 = 180°
3x = 120°
x = 40°
therefore the angles are 40°, 70° (40 + 30), and 70°
hope it answers your query
Answered by
7
Let the base angles be x,
Thus vertex angle = x+ 30,
therefore,
x+ x + x+30 = 180
3x + 30 = 180
x= 180-30/3
x = 50
therefore,
base angles each are 50 degrees
while the vertex angle is 50+30 = 80
Thus vertex angle = x+ 30,
therefore,
x+ x + x+30 = 180
3x + 30 = 180
x= 180-30/3
x = 50
therefore,
base angles each are 50 degrees
while the vertex angle is 50+30 = 80
Gaurav1402:
Actually its vice versa since the base angles are 30 more than vertex angle
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