Question

in an isosceles triangle ABC right angled at C prove that AB is equal to 2AC​

Answer 1

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➡Given: ABC is an isosceles triangle right angled at C.

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➡Let AC=BC

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➡In ABC,

By Pythagoras theorem

${ab}^{2} = {ac}^{2} + {bc}^{2}$

${ab}^{2} = {ac}^{2} + {ac}^{2}$

${ab}^{2} = 2. {ac}^{2}$

$ac = bc$

Hence proved ⤴

Answer 2

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Refer the attachment.