In an isosceles triangle ABC show that the bisector of its vertical angle bisects the base at right angel
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Step-by-step explanation:
Let a line bisect angle A and intersect BC at D.
In triangles ABD & ACD,
AB=AC.......given
AD =AD .....common
angle BAD = angle CAD.....angle bisector
Therefore by SAS ,they are congruent.
Therefore angles BDA=CDA.=90 degree .
and BD=CD ....by corresponding parts of congruent triangles.
Proved
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