Question

in an isosceles triangle ABC , the bisector of angle B and angle C meet at a point O. If angle A=40 degree , then angle BOA =? ​

Answer 1

Answer:

angle BOA IS 110 DEGREES

Answer 2

Answer: In triangle ABC

AB=AC

x = x

x + x + angle A = 180

2x + 40 = 180

2x = 180-40

2x = 140

x = 140/2

x = 70

A = 40

B = 70

C = 70

In triangle OBA

Bisector of angle B and angle C meet at O.

Then,Angle OBC = 1/2 of angle ABC and

Angle OCB = 1/2 of angle ACB

Angle OBC = 1/2 * 70

= 35

Angle OCB = 1/2 * 70

= 35

Angle OBC = Angle OCB

x = x

x + x + Angle BOA = 180

35 + 35 + Angle BOA = 180

Angle BOA = 180-70

Angle BOA = 110