Math, asked by varshasharadkale, 19 days ago

In an isosceles triangle ABC, the measure of vertex angle A is 30° more than the measure of each base angle. Find the measure of each angle of the triangle ​

Answers

Answered by shradhagaur2002
5

The measure of the vertex angle A of the given triangle is 80° and the measure of each base angle is 50°.

Given:-

an isosceles triangle whose vertex angle is 30° more than its base angle.

To find:-

The measure of each angle of the triangle.

Solution:-

  • A triangle is a closed polygon with three sides and hence three angles.
  • The sum of all the three angles of a triangle = 180° and this is known as the angle sum property.

Here,

Let the measure of each base angle B and C be 'x'

then the measure of vertex angle A = x+30°

According to the angle sum property,

A+ B+ C=180°

x+x+x+30°=180°

3x + 30°= 180°

3x= 180° - 30°

3x= 150°

x= 150°/3

x=50°

therefore measure of each base angle= 50°

the measure of the vertex angle= x+30°

= 50°+30°

= 80°

Answered by Mysteryboy01
2

The Answer is in Attachment

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