In an isosceles triangle ABC with AB=AC ,a circle passing through b and c INTERSECTS THE SIDES AB AND intersects the sides AB and AC AT D and E respectively .prove that DE is parallel to side BC
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2
Answer:
AB=AC
then a is common to DE and BC
ADE =ABC
AD=AB
DE=BC
AE=Ac
DE=BC
therefore DE is parallel to BC
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0
Step-by-step explanation:
ab acha is common to ab then de is parallel to bc
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