Question

in an isosceles triangle abc , with ab=ac,side ba is produced to D such that AB =AD. Then the measurement of angle BCD is​

Answer 1

Answer:

A

1

In triangle ABC,

AB = AC, so , ∠ABC=∠ACB

Now, since, AB =AD then, AC = AD

hence, ∠ACD=∠ADC

Now, let ∠ABC=∠ACB=x and ∠ACD=∠ADC=y

so, ∠ABC+∠BCD+∠BDC=180

∠ABC+∠ACB+∠ACD+∠BDC=180

x+x+y+y=180

2(x+y)=180

x+y=90

∠ACB+∠ACD=90

∠BCD=90

Step-by-step explanation:

Correct option is

A

1

In triangle ABC,

AB = AC, so , ∠ABC=∠ACB

Now, since, AB =AD then, AC = AD

hence, ∠ACD=∠ADC

Now, let ∠ABC=∠ACB=x and ∠ACD=∠ADC=y

so, ∠ABC+∠BCD+∠BDC=180

∠ABC+∠ACB+∠ACD+∠BDC=180

x+x+y+y=180

2(x+y)=180

x+y=90

∠ACB+∠ACD=90

∠BCD=90