in an isosceles TRIANGLE ABC, WITH AB=AC, THE BISECTOR OF ANGLE B AND ANGLE C INTERSECT EACH OTHER AT O. JOIN A TO O
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b=c
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Answer: To Find: (i) OB = OC (ii) AO bisects <A
(i) Consider, ΔAOB ≅ ΔAOC
= AB = AC (Given)
= <B = <C (∵ AB = AC)
= 1/2 <B = 1/2 <C
= <ABO = <ACO (Opposite angles)
= OA = OA (Common Side)
∴ By SAS Congruence rule,
= ΔAOB ≅ ΔAOC (C.P.C.T)
= <BAD = <OAC (CPCT)
= OB = OC (CPCT)
(ii) Show that AO bisects <A
= AO bisects <A (CPCT)
= ΔAOB ≅ ΔAOC
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