Question

in an isosceles triangle ABC with AB=AC the bisectors of angle A and angle C intersect each other at O.Show that;
(i)OB=OC (ii)AO bisects angle A

Answer 1

Answer:

TO PROVE.

(i) OB=OC

(ii) AO bisects angle A

PROOF.

In triangleAOB and AOC

AB=AC

AO=AO

angle BAO=angle COA

BY CPCT.

OB=OC

and A is bisector of angle A then it bisects it

Step-by-step explanation:

HOPE IT WILL HELP U....

Answer 2

Answer:

PLZ MARK AS BRAINLIEST.

Step-by-step explanation:

GIVEN

In ABC

AB=AC

Angle 1 =AngLe 2 &

Angle 3=4

TO PROVE

i)OB=OC

ii)AO biSects /_A

PROOF✅

i)As AB=AC (GIVEN)

Therefire /_ABC=/_ACB [OPPOSITE ANGLE OF EQUAL SIDES)

1/2AngLe ABC=1/2AngLe ACB

            /_2=/_4

So,OB=OC (OPPOSITE SIDES OF EQUAL ANGLES)

ii)In AOB & AOC

      AB=AC (GIVEN)

     OB=OC (PROVED)

     OA=OA (COMMON)

Therefore,AOB congruence to AOC (S.S.S.CONG..)

  /_5=/_6(CPCT)

So, OA bisects angles A.