In an isosceles triangle ABC , with AB = AC , the bisectors of angle b and C intersect each other at O. Join A to O.
Show that i) OB = OC
ii) AO bisects angle A
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Given :- In triangle ABC
AB = AC
BO is the bisector of angle B.
Therefore, angle 1 = angle 2
== CO is the bisector of angle C.
Therefore , angle 3 = angle 4.
To proof :- i) OB = OC
ii) AO bisects angle A.
Proof :- In triangle ABC
i) AB = AC
ii) angle B = angle C.
or angle 1 + angle 2 = angle 3 + angle 4
= (angle 1 = angle 2 and angle 3 = angle 4).
Therefore , 2 angle 2 = 2 Angle 4
=> angle 2 = angle 4
Therefore, OB = OC (sides opposite to equal angles are equal).
ii) In triangle ABO and triangle ACO.
AO = OA (common)
AB = AC (given)
OB = OC (from 3rd)
Therefore , ABO congruent ACO (SSS)
Angle 5 = angle 6 (cpct).
AO bisects angle A.
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