Question

in an isosceles triangle abc with ab=ac the bisectors of angle b and angle c intersect at o​

Answer 1

Answer:

Question incomplete

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Answer 2

Answer:

Since,

AB=AC..........(1)

OB is the bisector of ∠B

So, ∠ABO=∠OBC=

2

1

∠B.......(2)

OC is the bisector of ∠C

So, ∠ACO=∠OCB=

2

1

∠C.......(3)

⇒∠ACB=∠ABC (Angles opposite to equal sides are equal)

2

1

∠ACB=

2

1

∠ABC

∠OCB=∠OBC From (2) and (3)

Hence,

OB=OC (Sides opposite to equal angles are equal)

Hence proved.