in an isosceles triangle ABC with AB is equals to AC,D and E are points on BC such that B is equals to CD show that AD is equals to AE?
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here your ans hope this help
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toshi5:
i cant understand this
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Heya !!
Here's your answer.. ⬇⬇
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⚫ Given :- In isosceles ∆ABC, AB = AC
BE = CD
⚫ To Prove :- AD = AE
⚫ Proof :- AB = AC
angle C = angle B ----( opposite angles of equal sides are also equal. ) ( eq.1 )
In ∆ACD and ∆ABE,
AB = AC ----- ( Given )
angle C = angle B ----- ( from eq.1 )
BE = CD ----- ( Given )
By SAS congruence ∆ACD = ∆ABE.
Hence, AD = AE -- ( Proved )
_____________________________
Hope it helps..
Thanks :)
Here's your answer.. ⬇⬇
______________________________
⚫ Given :- In isosceles ∆ABC, AB = AC
BE = CD
⚫ To Prove :- AD = AE
⚫ Proof :- AB = AC
angle C = angle B ----( opposite angles of equal sides are also equal. ) ( eq.1 )
In ∆ACD and ∆ABE,
AB = AC ----- ( Given )
angle C = angle B ----- ( from eq.1 )
BE = CD ----- ( Given )
By SAS congruence ∆ACD = ∆ABE.
Hence, AD = AE -- ( Proved )
_____________________________
Hope it helps..
Thanks :)
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