Question

in an isosceles triangle,base angle are equak.vertex angle is 40 degree.what are base angles of triangle​

Answer 1

Answer:

70°

Step-by-step explanation:

Let the base angles be x°

Vertex angle=40°

Sum of angles of a ∆=180°

x+x+40°=180°

2x=180-40

2x=140°

x=140/2

x=70°

Base angles of ∆ are 70° each.