Question

in an isosceles triangle, base angle are equak.vertex angle is 40 degree.what are base angles of triangle ​

Answer 1

Answer:

your answer is 140.

Hope it helps

Answer 2

sum of all angles of triangle = 180⁰

base angles = X

now we solve that

now we solve that = X+ X+ 40⁰ = 180⁰

now we solve that = X+ X+ 40⁰ = 180⁰= 2X +40⁰= 180⁰

now we solve that = X+ X+ 40⁰ = 180⁰= 2X +40⁰= 180⁰= 2X = 180⁰-40⁰

now we solve that = X+ X+ 40⁰ = 180⁰= 2X +40⁰= 180⁰= 2X = 180⁰-40⁰= 2X = 140⁰

now we solve that = X+ X+ 40⁰ = 180⁰= 2X +40⁰= 180⁰= 2X = 180⁰-40⁰= 2X = 140⁰= X = 140⁰/2

now we solve that = X+ X+ 40⁰ = 180⁰= 2X +40⁰= 180⁰= 2X = 180⁰-40⁰= 2X = 140⁰= X = 140⁰/2 = X = 70⁰

so, base angles is equal to 70⁰

to check

=70⁰+70⁰+40⁰=180⁰

= 180⁰=180⁰

hence proved

hope this helps you

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