Math, asked by unknownguy1200, 10 months ago

In an isosceles triangle base is 20 cm and it's equal side is 16 cm find its area and height

Answers

Answered by NishaShiwangi
0

Answer:

area= 128 cm2.

Height=16.(2)1/2 cm.

Step-by-step explanation:

Here ,, Base of isosceles triangle is equal to 20 cm

and two equal sides are 16 cm.

Now ,,

  • Area = 1/2 .(side) 2
  • = 1× ( 16) 2/ 2
  • = 256÷ 2
  • =128 cm2.

  1. Height = (2)1/2.side

=(2)1/2.16

=16.(2)1/2 cm.

Answered by manish17292
1

Answer:

Height = 12

Area = 120 cm sq.

Step-by-step explanation:

To find the Height of Isosceles Triangle

First U need to use Pythagoras Theorem

which is - hypotenuse square = perpendicular square + base square.

now, 16 square + 20 square,

256 =perpendicular square + 400,

now Height = 12

Area of Triangle = ½ × b× h

½ × 12×20

12×10

= 120

Similar questions