In an isosceles triangle base is 20 cm and it's equal side is 16 cm find its area and height
Answers
Answered by
0
Answer:
area= 128 cm2.
Height=16.(2)1/2 cm.
Step-by-step explanation:
Here ,, Base of isosceles triangle is equal to 20 cm
and two equal sides are 16 cm.
Now ,,
- Area = 1/2 .(side) 2
- = 1× ( 16) 2/ 2
- = 256÷ 2
- =128 cm2.
- Height = (2)1/2.side
=(2)1/2.16
=16.(2)1/2 cm.
Answered by
1
Answer:
Height = 12
Area = 120 cm sq.
Step-by-step explanation:
To find the Height of Isosceles Triangle
First U need to use Pythagoras Theorem
which is - hypotenuse square = perpendicular square + base square.
now, 16 square + 20 square,
256 =perpendicular square + 400,
now Height = 12
Area of Triangle = ½ × b× h
½ × 12×20
12×10
= 120
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