Question

in an isosceles triangle each base angle is half the vertical angle. Calculate the angles of triangle.

Answer 1

Answer:

Let angleBAC = x

so, angle ABC = angle ACB = x÷2

By angle sum property in triangle ABC

$x + \frac{x}{2} + \frac{x}{2} = 180$

4x÷2 = 180

2x = 180

x =90

Therefore,

angle BAC =90

angle ABC = angle ACB = 45