Question

In an isosceles triangle each base is 30° greater than the vertical angle. Find the measure of all the three angles of triangle.

Answer 1

Solution:
Hence,w.k.t
Sum of all angles of a ∆ = 180°
Let the verticle angle be x.
therefore, x + (x+30) +(x+30) = 180°
3x+60 = 180°
3x = 180-60
x = 120/3
x = 40°
Hence, 1st angle = 40°
2nd angle = x+30 = 40+30 = 70°
3rd angle = x+30 = 40+30 = 70°
Thanks for asking