in an isosceles triangle each base triangle is four times of it vertical angel find all the angels of the triangle
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let ABC be the isoceles triangle with side AB = AC
hence angle B = angle C
but also given that
Angle B = 4(angleA)
Let the angle A be x
ATQ
angle A +B+C = 180
x + 4x + 4x = 180
9x =180
x = 20
Angle A = 20
Angle B = 80
Angle C =80
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