Question

in an isosceles triangle if the length of its side is a b equal to 10 cm AC = 5 cm and BC = 8 cm find the length of its attitude drawn from a on BC​

Answer 1

Answer:

In ΔABC, AD=6cm and BC=9cm

Area of triangle=

2

1

×base×height=

2

1

×BC×AD

=

2

1

×9×6=27 cm

2

Again, Area of triangle=

2

1

×base×height=

2

1

×AB×CE

⇒27=

2

1

×7.5×CE

⇒ CE=

7.5

27×2

⇒ CE=7.2cm

Thus, height from C to AB i.e., CE is 7.2cm.