Question

In an isosceles triangle , if the vertex angle is twice the sum of the base angles, calculate the angles of the triangle
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Answer 1

Answer:

Let each base angle be x in an isosceles △ABC

Then vertex angle be 2(x+x)=4x

Since sum of angles of a triangle is 180

o

.

Hence 4x+x+x=180

o

⇒6x=180

0

⇒x=30

0

∴ Angles are 30

o

,30

o

,120

o

Step-by-step explanation:

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Answer 2

Answer:

let vertex angle be x

and base angles be y(will be same as its an isosceles tri)

2x= y+y

2x= 2y

the angles are 45⁰...45⁰ (base angles)and 90⁰(vertex angle)