In an isosceles triangle, if the vertex angle is twice the sum of the base angles, calculate the angle of triangle...
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Let angle A be the angle of twice sum of base angles ,A=2(x+ x)
angle B = x
Angle C = x
=>2(x+x) + x + x = 180
=> 2x +2x + 2x = 180
= 6x = 180
x = 30
Now u can find the angles by putting value of x in above statements.
Hope it helps
Pls mark me brainliest :)
Let angle A be the angle of twice sum of base angles ,A=2(x+ x)
angle B = x
Angle C = x
=>2(x+x) + x + x = 180
=> 2x +2x + 2x = 180
= 6x = 180
x = 30
Now u can find the angles by putting value of x in above statements.
Hope it helps
Pls mark me brainliest :)
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