Question

In an isosceles triangle PQR PQ = QR and PR^2=2PR^2 . prove that angle Q is a right angle​

Answer 1

Answer:

M be the mid point of PR.

Join Q &M

sin ∠PQM =PM/PQ = PR/(2PQ)

(sin ∠PQM ) ^2,= PR^2 /(4 PQ^2) = 2PQ^2/4PQ^2 = 1/2

sin ∠PQM = 1/√2

∠PQM = 45 °

∠PQR = 90 °

Or

PR^2= 2 PQ^2

PR^2= ( PQ + PQ) ^ 2

PR^2= ( PQ + QR) ^ 2. Since PQ = QR

Triangle PQR is a right angled triangle with ∠PQR = 90 °

Step-by-step explanation:

Answer 2

Step-by-step explanation:

I this this will satisfy u