Question

In an isosceles triangle PQR where PQ = PR.
the ratio of the lengths of the sides PQ and Q R
is 5:9 If the perimeter of the triangle is
38.cm, find the lengths of PQ,PR and QR?​

Answer 1

Answer:

PQ=PR=10,PR=18

Step-by-step explanation:

Let PR=PQ=5x

And, QR=9x

Perimeter of triangle = sum of all sides

PR+PQ+QR=38

5x+5x+9x=38

19x=38

x=38/19

x=2

Hence, PR=PQ=5x=5*2=10

QR=9*2=18

Answer 2

we know the ratio between sides.

5:9:5

so let the common multiple be x

5x +9x + 5x = 38 cm

19x =38

x=2cm

PQ=PR=5x =10 cm

QR=9x=18 cm

Step-by-step explanation: