Question

In an isosceles triangle, prove that the altitude from the vertex bisects the base.​

Answer 1

Answer:

let us take a triangle ABC and draw an altitude CD

being an isosceles triangle

in ΔACD and ΔCDB

CD=CD (common )

CA=CB ( equal opposite sides)

∠ A=∠ B ( angle opposite to opposite sides are also equal )

therefore : ΔACD and ΔCDB are congruent by ASA rule

so , AD=DB by CPCT

So, its true

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

This is the explanation of your answer