In an isosceles triangle, the angle bisector of the vertical angle coincides with its what part?
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In the given triangle, the bisector triangle of the vertical angle concurs with its base at a right angle.
- Suppose ΔABC be the isosceles triangle having AB=AC and AD as their vertical angle bisector
- AB is equal to AC∠B which is equal to ∠C∠BAD=∠CAD
- So by ASA principles, the triangles are congruent that is BD=DC
- Consequently, the bisector of vertical angle intersects the base
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