In an isosceles triangle, the base angle are equal. The vertex angle is 5/2 times of either base angle angle . What are the angle of the triangle?
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Answer:
Let, the base angles be X+X=2x
therefore, the vertex angle=5/2×x=5x/2
Now,
5x/2 +2x=180°. [Since, sum of all the
angles of a triangle
is180°]
5x/2 +4x/2=180
9x/2=180
9x=180×2
9x=360
x=360/9=40°
Therefore,the angles are—
1. X=40°
2.X=40°
3.5/2×x=5/2×40=5×20 =100°
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