Question

In an isosceles triangle the base angle is 40 more than two times its vertical angel find all the angle of the triangle​

Answer 1

Answer:

all angles are 20°, 80° & 80°

Step-by-step explanation:

in isosceles triangle two sides are equal

so, angels opposite to equal side are also equal means,

base angles are equal

let the vertical angles be x

so, base angle= 40+2x

sum of interior angles of triangle= 180°

x+(40+2x)+(40+2x) = 180°

x+40+2x+40+2x= 180°

5x+80= 180°

5x= 180-80

x= 100/5

x= 20°

base angles= 40+2x = 40+2(20)= 40+40= 80°

Answer 2

Let vertical angle of an isosceles triangle = x

∴ Each base angle = 4x

∴ x + 4x + 4x = 180°

(Sum of angles of a triangle)

⇒ 9x = 180° ⇒ x = 180°/9 = 20°

∴ Vertical angle = 20°

and each of the base angle = 4x

= 4 x 20° = 80°